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Sa se rezolve in multimea numerelor complexe [tex] x^{2} +8x+25=o[/tex]....stie cineva?

Răspuns :

x²+8x+25=0
Δ=b²-4ac=64-4.24=64-100=-36
x1,2=(-b+,-√Δ)/2a
x1=(-8-√-36)/2
dar √-1=√i²=i
x1=(-8-6i)/2=-4-3i∈C
x2=-4+3i∈C