2014 = 2 × 1007
(1 ×2 ×3 × 4 × ... × 1006 × 1007 × 1008 × ... × 2013) : 2014 =
= 1 × 3 × 4 × ... × 1006 × 1008 × ... × 2013
=> 1 ×2 ×3 × 4 × ... × 1006 × 1007 × 1008 × ... × 2013 =
2014(1 × 3 × 4 × ... × 1006 × 1008 × ... × 2013)
Notam numarul (1 × 3 × 4 × ... × 1006 × 1008 × ... × 2013) cu n.
=> 1 ×2 ×3 ×... × 2013 = 2014n
=> 1 ×2 ×3 ×... × 2013 + 2013 = 2014n + 2013
(2014n + 2013) : 2014 = n rest 2013
Restul impartirii = 2013