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Calculati si la rezultat reduceti termeni asemenea :
(2x-1)²+(3x+2)²+(x-6)(x+6)=
(3a-2)²-(2a-3)²-(a+5)(a-5)=


Răspuns :

(2x-1)²+(3x+2)²+(x-6)(x+6)=
=4x²-4x+1+9x²+12x+4+x²-36=
=14x²+8x-31


(3a-2)²-(2a-3)²-(a+5)(a-5)=
=9a²-12a+4-4a²+12a-9-a²+25=
=4a²+20=4(a+5)