M FeO = M Fe + M O = 56 + 16 = 72
72 g FeO.....................56gFe
100 g Feo....................x
x=100·56:72 = 77,77g Fe (deci 77% Fe in FeO)
M Fe2O3 = 2·M Fe + 3·M O = 2·56 +3·16 = 160
160 g Fe2O3..................2·56g Fe
100................................y
y= 70 g Fe (deci 70% Fe in Fe2O3)
M Fe3O4 = 3·56 + 4·16 = 232
232 g Fe3O4.............................3·56g Fe
100 g..........................................z
z=72,41g Fe (deci 72,41% Fe in Fe3O4)
CONCLUZIE: FeO are cel mai mare procent de Fe
