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Va rog ajutati-ma la acest exercitiu!!! Descompuneti in factori: 2x^2 +4x-5.

Răspuns :

2x²+4x-5=2(x²+2-2,5)
a=1
b=2
c=-2,5
Δ=b²-4ac=2²-[4x1x(-2,5)]=4+10=14
x₁,₂ =( -b+/-√Δ)/2a=(-2+/-√14)/2
x₁ =(-2+√14)/2=-1+√14/2
x₂ =(-2-√14)/2=-1-√14/2
2x²+4x-5=2(x+1-√14/2)(x+1+√14/2)