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Aflati volumul unei prisme hexagonale regulate cu inaltimea de 5 cm si aria laterala de 120 cm patrati. Va rog !

Răspuns :

Al=Pb*h
120=Pb*5
Pb=120:5
Pb=24
Pb=6l
l=24:6
l=4
Ab=6*l²√3/4
Ab=6*4²√3/4
Ab=24√3
V=Ab*h
V=24√3*5
V=120√3
Al=Pbxh
120=Pbx5
Pb=120:5
Pb=24
Pb=6l
l=24:6
l=4
Ab=6xl²√3/4
Ab=6x4²√3/4
Ab=24√3
V=Abxh
V=24√3x5
V=120√3
 
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