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Rezolvati in multimea numerelor reale ecuatia: 2 la puterea 2x +3 ori 4 la puterea x-16=0

Răspuns :

[tex] 2^{2x} +3* 4^{x} -16=0[/tex]⇔[tex] (2^{2})^{x} +3*(2^{2})^{x}=16[/tex]⇔
[tex]4*(2^{2})^{x}=16 \ | :4[/tex]⇒[tex]4^{x}= 4^{1} [/tex]⇒[tex]x=1[/tex]
Solutia ecuatiei este: [tex]S=\{1\}[/tex]