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Fie functia f:R-->R , F(x)= -2x+[tex] \sqrt{6} [/tex] . Aratati ca a = [tex] \frac{f( \sqrt{3} )-f( \sqrt{2} )}{ \sqrt{2}- \sqrt{3} } [/tex] ∈ N

Răspuns :

[tex] \frac{(-2 \sqrt{3}+ \sqrt{6}+2 \sqrt{2} - \sqrt{6} )}{ \sqrt{2}- \sqrt{3} } [/tex]
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