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9 la puterea 2011; scrieti.l ca o suma de cuburi perfecte

Răspuns :

[tex] 9^{2011} [/tex] = 9*[tex] 9^{2011} [/tex] =

= ([tex] 1^{3} + 2^{3} [/tex])[tex] ( 3^{2} )^{3*670} [/tex] =

= ([tex] 1^{3} + 2^{3} [/tex])[tex] ( 3^{2*670} )^{3} [/tex] =

= [tex] ( 3^{1340} )^{3} + (2* 3^{1340} )^{3} [/tex]