👤

Determinati perechile de numere reale (a,b) pentru care are loc egalitatea : 
[tex] \frac{a-1}{2} [/tex] = [tex] \frac{3}{b+1} [/tex] . 


Răspuns :

[tex]\dfrac{a-1}{2}=\dfrac{3}{b+1}\Rightarrow a=\dfrac{6}{b+1}+1=\dfrac{b+7}{b+1}[/tex]

luam [tex]b=m\in\mathbb R[/tex] si avem:

[tex](a;b)\in\left\{\left(\dfrac{m+7}{m+1};\ m\right)|m\in\mathbb R\right\}[/tex]