a+b+c+d=350
b = [tex] \frac{3}{2} *a[/tex]
c = [tex] \frac{4}{3} *b[/tex] = [tex] \frac{4}{3} * \frac{3}{2} *a[/tex] =2a
d = [tex] \frac{5}{4} *c[/tex] = [tex] \frac{5}{4} *2a[/tex] = [tex] \frac{5}{2} *a[/tex]
Inlocuim in prima relatie:
a+[tex] \frac{3}{2} *a[/tex]+2a+[tex] \frac{5}{2} *a[/tex]=350 Inmultim ambii membri cu 2:
2a+3a+4a+5a=700
14a=700
a=50
b=[tex] \frac{3}{2} *50[/tex]=3*25=75
c=2*50=100
d=[tex] \frac{5}{2} *50[/tex]=5*25=125