👤

0,8 + 2 SUPRA3 =
3,05 -7SUPRA 40=


Răspuns :

0,8=8\10=>8\10+2\3  aduci la acelasi numitor acesta fiind 30 si avem:24\30+20\30=44\30 se simplifica prin 2 si ramane:22\15=1si 7/15
3,05-7/40=305/100-7/40 aduci la acelasi numitor aceste fiind 200 si avem:
610/200-35/200=575/200  se simplifica prin 25 si ramane :23/8
0,8+[tex] \frac{2}{3} [/tex]=[tex] \frac{8}{10}+ \frac{2}{3}= \frac{4}{5}+ \frac{2}{3}= \frac{12+10}{15}= \frac{22}{15} [/tex]
3,05-[tex] \frac{7}{40}= \frac{305}{100}- \frac{7}{40}= \frac{61}{20}- \frac{7}{40}= \frac{122-7}{40}= \frac{115}{40}= \frac{23}{8} [/tex]