[tex] \frac{3x+11}{6} + \frac{x-7}{2} < \frac{5x-1}{12} -2 \frac{1}{6}[/tex]
[tex]\frac{3x+11}{6} + \frac{x-7}{2} < \frac{5x-1}{12} - \frac{13}{6}[/tex]
(inmultim ambii membri ai inecuatiei cu 12 si obtinem:)
2(3x+11) + 6(x-7) < 5x-1 - 2(13)
6x+22 + 6x-42 < 5x-1 - 26
12x - 20 < 5x - 27
12x - 5x < -27 - 20
7x < -47
x < -47 : 7
x < -6,714
x ∈ ( -∞ , -6,714 )
