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rezolvati inecuatiia (x+2)²-(x+2)(x-5) mai mic ca 14x-7

Răspuns :

x²+4x+4-x²+5x-2x+10<14x-7
7x+14<14x-7
21<7x
x>3
x∈(3; ∞)
Sper ca te-am ajutat. :)
[tex]\rm (x+2)^2-(x+2)(x-5)<14x-7 \\ \not x^2+4x+4-\not x^2+5x-2x+10<14x-7 \\ 7x+14<14x-7|:7 \\ x+2<2x-1 \\ 2x-x>2+1 \\ x>3 \\ \\ \boxed{x \in (3;\infty)}[/tex]