82g 10moli
CH₂=CH-CH₂-CH₂-CH=CH₂ + 10[O] -> 2CO₂ + 2H₂O + HOOC-(CH₂)₂-COOH
8,2g x=?
x=8,2x10/82=1mol
2moli 5moli
2KMnO₄ + 3H₂SO₄ -> K₂SO₄ + 2MnSO₄+ 3H₂O + 5[O]
y=? 1mol
y=1x2/5=2/5=0,4moli
Cm=[tex] \frac{n}{ V_{s} } [/tex] => Vs = [tex] \frac{n}{Cm} = \frac{0,4moli}{0,2mol/L} = 2L[/tex] KMnO₄
Tu poate o stii asa:
5CH₂=CH-CH₂-CH₂-CH=CH₂ + 2KMnO₄ + 3H₂SO₄ -> 10CO₂ + 10H₂O + 5HOOC-(CH₂)₂-COOH + K₂SO₄ + 2MnSO₄+ 3H₂O
