👤

Cum descompun in factori relatia:
(3x-5)^2-(2x+1)^2 ??


Răspuns :

[tex]Dupa~formula~de~calcul~ a^{2} - b^{2} =(a+b)(a-b),~unde~a=3x-5 \\ si~b=2x+1. \\ \\ (3x-5)^{2} - (2x+1)^{2} =[(3x-5)+(2x+1)][(3x-5)-(2x-1)]= \\ \\ =\boxed{(5x-4)(x-4)}.[/tex]