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(2x+1)la puterea a 2-a -3(x+2)la puterea a 2-a=2(7-4x)

Răspuns :

4x²+4x+1-3(x²+4x+4)=14-8x
4x²+4x+1-3x²-12x-12-14+8x=0
x²-25=0
x²=25
x1=√25
x1=5
x2=-√25
x2=-5
S={-5,5}
[tex](2x+1)^{2} -3(x+2)^{2}=2(7-4x)[/tex]
[tex](4x^{2}+4x+1) -3(x^{2}+4x+4)=14-8x[/tex]
[tex](4x^{2}+4x+1) -(3x^{2}+12x+12)=14-8x[/tex]
[tex]4x^{2}+4x+1 -3x^{2}-12x-12+8x-14=0[/tex]
[tex]x^{2}-25=0[/tex]
[tex]x^{2}=25[/tex]
x = +5 sau -5