[tex]Dup\u{a}\;consum\;r\u{a}m\^ane:\\butoiul\,I\;\;\;\;...\;8\cdot\frac{1}{8}=1\; litru\;;\\
butoiul\,II\;\;...\;(8:2)\cdot\frac{1}{4}=4\,litrii\,\cdot\frac{1}{4}=1\,litru\;;\\
In\;cele\;doua\;butoaie\; a \;ramas\\(8-1)+(4-1)=7+3=10 \;litrii\;de\;vin[/tex]