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Aflati numarul x,stiind ca:{[(1,43)²]la puterea17}³=1,43 sus x-1.

Răspuns :

                                               
[tex]\{ [(1,43)^2]^{17}\}^3 = 1,43^{x-1} \\ \\ 1,43^{2*17*3} = 1,43^{x-1} \\ \\ 2*17*3=x-1 \\ 102 = x-1 \\ x-1=102 \\ x=102+1=\boxed{103}[/tex]