Aldehida: CnH2n+1-CH=O
2CnH2n+1CH=O -> CnH2n+1-CH(OH)-CnH2n-CH=O (B)
o vom rescrie astfel: C2n+1H4n+3O-CH=O
dar hai sa notam cu S-partea de dinainte de CH=O
S+29.........................................................216g
S-CH=O + 2(Ag(NH3)2)OH -> S-COOH + 2Ag + 4NH3 + H2O
1,16g.................................................2,16g
S+29=1,16*216/2,16=116
S=116-29=87
S=MC2n+1H4n+3O=24n+12+4n+3+16=28n+31=87 => 28n=56 => n=2
aldehida are formula C2H5-CH=O
adica CH3-CH2-CH=O - propanalul
