glucoza: C₆H₁₂O₆
amidon si celuloza: (C₆H₁₀O₅)n
1. raportul atomic
glucoza: C:H:O=6:12:6=1:2:1
celuloza si amidon: C:H:O=6n:10n:5n=6:10:5
2. raport de masa
glucoza: M=12*6+12+16*6=72+12+96=180g/mol
180...........100%
72................x% => x=72*100/180=40%
12................y% => y=12*100/180=6,6666%
96................z% => z=96*100/180=53,333%
amidon si celuloza: M=12*6+10+16*5=72+10+80=162g/mol
162n.........100%
72n..............x% => x=72n*100/162n=44,4444%
10n..............y% => y=10n*100/162n=6,1728%
80n..............z% => z=80n*100/162n=49,3828%
