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media geometrica a numerelor a=|2 radical din 7 - 8| si b=| 2 radical din 7 + 8|

Răspuns :

[tex] \sqrt{28} \ \textless \ \sqrt{64} =\ \textgreater \ |2 \sqrt{7} -8| \ \textless \ 0 =\ \textgreater \ |2 \sqrt{7} -8|=8- 2\sqrt{7} [/tex]

[tex]|2 \sqrt{7} +8| \ \textgreater \ 0 =\ \textgreater \ |2 \sqrt{7} +8 | = 2 \sqrt{7}+8 [/tex]

[tex]mg= \sqrt{a*b}= \sqrt{(8- 2 \sqrt{7})(8+2 \sqrt{7}) }= \sqrt{64-28} = \sqrt{36} =6[/tex]