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( ab + ba) : ( a+b ) = x- 2014......

Aflati " x" din egalitatea de mai sus.



VA rog repede !!! :)


Răspuns :

ab+ba=10a+b+10b+a=11a+11b=11(a+b)
11(a+b):(a+b)=x-2014
11=x-2014=x=2025
ab+ba=10a+b+10b+1=11a+11b=11[a+b]
⇒11[a+b]:[a+b]=x-2014
⇒se reduce [a+b] cu [a+b];
⇒11=x-2014
⇒x=11+2014
⇒x=2025;