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a supra 11 si b supra 3
7a-2b supra 3a+5b
urgentt va rog


Răspuns :

[tex] \frac{a}{11}= \frac{b}{3}
          \frac{7a-2b}{3a+5b} \frac{a}{b}= \frac{11}{3}
Deci \frac{7*11-2*3}{3*11+5*3}=  \frac{77-6}{33+15}= \frac{71}{48} [/tex]
AM EXERCITIUL PE CAIET!
 E BINE FACUT
  a/11=b/3=>a/b=11/3
7a-2b/3a+5b=7*11-2*3/3*11+5*3=71/48