1. [tex] \frac{2}{b} = \frac{3}{5} =\ \textgreater \ 10=3b =\ \textgreater \ b= \frac{3}{10} [/tex]
a+[tex] \frac{3}{10} = 16[/tex]
10a + 3 = 160
10a = 157 => a= 15,7
2. [tex] \frac{x}{y} = 0.(6) =\ \textgreater \ 0,(6)y=x =\ \textgreater \ \frac{0,(6)y}{0,(6)y}+y = 1+y[/tex]